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MHT CET 2026 (16 Apr, Shift 1) · Superposition, Coherence & Intensity

Superposition, Coherence & Intensity question from MHT CET 2026 (16 Apr, Shift 1)

Q13MHT CET 2026 · 16 APR · SHIFT 1Medium

Superposition, Coherence & Intensity

The ratio of intensities at two points on the screen in Young's double slit experiment when waves from the two slits have a path difference of zero and $\lambda/4$ is ( $\lambda$ is the wavelength of light used) ( $\cos 0^\circ = 1,\ \cos\pi/2 = 0$ )

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Answer: (b)

$I = I_{max}\cos^2\dfrac{\phi}{2}$ , $\phi = \dfrac{2\pi}{\lambda}\Delta x$ .
$\Delta x = 0$ : $I_1 = I_{max}$ . $\Delta x = \lambda/4$ : $\phi = \pi/2$ , $I_2 = I_{max}/2$ .
So the answer is (b) $2 : 1$ .

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