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MHT CET 2023 (13 May, Shift 2) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2023 (13 May, Shift 2)

Q43MHT CET 2023 · 13 MAY · SHIFT 2Medium

Current Loop as a Magnetic Dipole

The ratio of magnetic field at the centre of the current carrying circular loop and magnetic moment is XX. When both the current and radius are doubled, then the ratio will be

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Answer: (d)

  1. X=BM=μ0I/2RIπR2=μ02πR3X = \frac{B}{M} = \frac{\mu_0 I/2R}{I\pi R^2} = \frac{\mu_0}{2\pi R^3}, independent of II.
  2. Doubling RR divides the ratio by 23=82^3 = 8.
  3. So the answer is (d) X8\frac{X}{8}.
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