Student Login

Home›Chapters›Moving Charges and Magnetism PYQs›Current Loop as a Magnetic Dipole›Question 7

MHT CET 2026 (18 Apr, Shift 1) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2026 (18 Apr, Shift 1)

Q7MHT CET 2026 · 18 APR · SHIFT 1Medium

Current Loop as a Magnetic Dipole

The ratio of magnetic field at the centre of the current carrying circular loop and its magnetic moment is ' $x$ '. When both the current and radius are tripled, then the ratio will be

Show answer and solution

Answer: (a)

$B = \frac{\mu_0 I}{2R}$ and $M = I\pi R^2$ .
$x = \frac{B}{M} = \frac{\mu_0}{2\pi R^3}$ , independent of $I$ .
Tripling $R$ gives $x' = \frac{x}{3^3}$ .
So the answer is (a) $\frac{x}{27}$ .

Report a mistake

More questions on Current Loop as a Magnetic Dipole

Two wires of same length are bent to form the circular loop with two turns and a square…MHT CET 2026 (17 Apr, Shift 2)
A circular coil of 'N' turns and diameter 'd' carries current 'I'. It is unwound and…MHT CET 2026 (15 Apr, Shift 1)
The magnetic flux near the axis and inside the air core solenoid of length 60 cm carrying…MHT CET 2026 (13 Apr, Shift 1)
A circular coil of N turns and diameter D carries current I. It is unwound and rewound to…MHT CET 2026 (11 Apr, Shift 2)
A 100-turn closely wound circular coil of radius 5 cm has a magnetic field of 3.14 × 10⁻³…NEET 2026
The relation between magnetic moment (M) of revolving electron of charge (e) and mass (m)…MHT CET 2026 (20 May, Shift 1)
A wire of length L is bent in the form of a circular coil and current ' i ' is passed…MHT CET 2026 (11 Apr, Shift 1)
A current carrying circular loop of radius 2 cm with unit normal n = (k + i)/(√(2)) is…JEE Main 2026 (8 Apr, Shift 2)