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MHT CET 2024 (4 May, Shift 2) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from MHT CET 2024 (4 May, Shift 2)

Q19MHT CET 2024 · 4 MAY · SHIFT 2Easy

Hydrogen Spectrum & Spectral Series

The ratio of minimum wavelengths of Lyman and Balmer series will be

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Answer: (b)

  1. Minimum wavelength = series limit: λmin=n12R\lambda_{min} = \frac{n_1^2}{R}.
  2. Lyman: 1R\frac{1}{R}; Balmer: 4R\frac{4}{R}.
  3. Ratio =0.25= 0.25.
  4. So the answer is (b) 0.25.
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