Physics Circle home Student Login

Home›Chapters›Atomic Structure PYQs›Hydrogen Spectrum & Spectral Series›Question 2

MHT CET 2026 (13 May, Shift 1) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from MHT CET 2026 (13 May, Shift 1)

Q2MHT CET 2026 · 13 MAY · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series

The ratio of minimum wavelengths of Lyman and Balmer series will be

Show answer and solution

Answer: (b)

  1. Minimum wavelength is the series limit (n2→∞n_2 \to \infty): 1λmin=Rn12\frac{1}{\lambda_{min}} = \frac{R}{n_1^2}.
  2. Lyman: λmin=1R\lambda_{min} = \frac{1}{R}; Balmer: λmin=4R\lambda_{min} = \frac{4}{R}.
  3. Ratio =14=0.25= \frac{1}{4} = 0.25.
  4. So the answer is (b) 0.250.25.
Report a mistake

More questions on Hydrogen Spectrum & Spectral Series