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MHT CET 2024 (15 May, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from MHT CET 2024 (15 May, Shift 1)

Q50MHT CET 2024 · 15 MAY · SHIFT 1Medium

Bohr Model: Orbits, Speed & Angular Momentum

The ratio of the areas of the electron orbits for the second excited state to the first excited state for the hydrogen atom is

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Answer: (d)

Second excited state $n = 3$ , first excited state $n = 2$ .
Area $= \pi r^2$ and $r \propto n^2$ , so area $\propto n^4$ .
$\frac{A_3}{A_2} = \frac{3^4}{2^4} = \frac{81}{16}$
So the answer is (d) $81 : 16$ .

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