The ratio of the density of oxygen nucleus (₈¹⁶O) and helium nucleus (₂⁴He) is (a) 1: 1 (b) 2: 1 (c) 4: 1 (d) 8: 1

Answer: (a). ρ = (Am)/(4/3π R₀³ A) = (3m)/(4π R₀³), independent of A. So all nuclei have the same density. So the answer is (a) 1: 1.

The ratio of the density of oxygen nucleus (₈¹⁶O) and helium nucleus… | MHT CET 2026 (16 Apr, Shift 2)

Q4MHT CET 2026 · 16 APR · SHIFT 2Easy

Nucleus: Composition, Size & Nuclear Force

The ratio of the density of oxygen nucleus $\left({}_{8}^{16}\text{O}\right)$ and helium nucleus $\left({}_{2}^{4}\text{He}\right)$ is

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Answer: (a)

$\rho = \frac{Am}{\frac{4}{3}\pi R_0^3 A} = \frac{3m}{4\pi R_0^3}$ , independent of $A$ .
So all nuclei have the same density.
So the answer is (a) $1 : 1$ .

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