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MHT CET 2019 (2 May, Shift 2) · Units & Dimensions

Units & Dimensions question from MHT CET 2019 (2 May, Shift 2)

Q79MHT CET 2019 · 2 MAY · SHIFT 2Easy

Units & Dimensions

The ratio of the dimensions of Planck's constant to that of moment of inertia is the dimensions of

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Answer: (c)

  1. [h]=[ML2T−1][h] = [\mathrm{ML^2T^{-1}}] (from E=hνE = h\nu); [I]=[ML2][I] = [\mathrm{ML^2}]
  2. [h][I]=[T−1]\frac{[h]}{[I]} = [\mathrm{T^{-1}}]
  3. So the answer is (c) frequency.
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