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MHT CET 2025 (26 Apr, Shift 1) · YDSE: Fringe Width & Fringe Positions

YDSE: Fringe Width & Fringe Positions question from MHT CET 2025 (26 Apr, Shift 1)

Q17MHT CET 2025 · 26 APR · SHIFT 1Medium

YDSE: Fringe Width & Fringe Positions

The ratio of the distance of $n$ th bright band and $m$ th dark band from the central bright band in an interference pattern is

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Answer: (c)

$n$ th bright: $y = n\beta$ ; $m$ th dark: $y = \left(m - \frac{1}{2}\right)\beta$
Ratio $= n : \left(m - \frac{1}{2}\right)$
So the answer is (c).

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