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MHT CET 2025 (26 Apr, Shift 1) · Simple Pendulum

Simple Pendulum question from MHT CET 2025 (26 Apr, Shift 1)

Q18MHT CET 2025 · 26 APR · SHIFT 1Easy

Simple Pendulum

The ratio of the frequencies of two simple pendulums is 4:34 : 3 at the same place. The ratio of their respective lengths is

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Answer: (c)

  1. f=12πgl⇒l∝1f2f = \frac{1}{2\pi}\sqrt{\frac{g}{l}} \Rightarrow l \propto \frac{1}{f^2}
  2. l1l2=(f2f1)2=(34)2=916\frac{l_1}{l_2} = \left(\frac{f_2}{f_1}\right)^2 = \left(\frac{3}{4}\right)^2 = \frac{9}{16}
  3. So the answer is (c) 9:169 : 16.
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