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NEET 1990 (AIPMT) · Nucleus: Composition, Size & Nuclear Force

Nucleus: Composition, Size & Nuclear Force question from NEET 1990 (AIPMT)

Q46NEET 1990 · AIPMTEasy

Nucleus: Composition, Size & Nuclear Force

The ratio of the radii of the nuclei ${}_{13}\text{Al}^{27}$ and ${}_{52}\text{Te}^{125}$ approximately

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Answer: (a)

$R \propto A^{1/3}$ , so $\frac{R_{Al}}{R_{Te}} = \left(\frac{27}{125}\right)^{1/3}$ .
$= \frac{3}{5} = \frac{6}{10}$
So the answer is (a) $6 : 10$ .

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