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MHT CET 2026 (15 Apr, Shift 2) · Heat Conduction

Heat Conduction question from MHT CET 2026 (15 Apr, Shift 2)

Q4MHT CET 2026 · 15 APR · SHIFT 2Easy

Heat Conduction

The ratio of the thermal conductivity of two rods of different materials is 6:5. The two rods of same area of cross section and same thermal resistance will have the length in the ratio

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Answer: (b)

  1. Thermal resistance R=LKAR = \frac{L}{KA}; same RR and AA gives L∝KL \propto K.
  2. L1L2=K1K2=65\frac{L_1}{L_2} = \frac{K_1}{K_2} = \frac{6}{5}
  3. So the answer is (b) 6:56:5.
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