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MHT CET 2025 (5 May, Shift 2) · Energy of the Electron & Energy Levels

Energy of the Electron & Energy Levels question from MHT CET 2025 (5 May, Shift 2)

Q9MHT CET 2025 · 5 MAY · SHIFT 2Medium

Energy of the Electron & Energy Levels

The ratio of the total energy of the 22nd orbit electron for the hydrogen atom ( 1H{}^{1}\text{H}) to that of a helium ion (He+\text{He}^{+}) is:

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Answer: (d)

  1. En∝Z2n2E_n \propto \frac{Z^2}{n^2}; same n=2n = 2, so E∝Z2E \propto Z^2.
  2. EHEHe+=1222=14\frac{E_H}{E_{He^+}} = \frac{1^2}{2^2} = \frac{1}{4}
  3. So the answer is (d) 14\frac{1}{4}.
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