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MHT CET 2024 (3 May, Shift 1) · Matter Waves: de Broglie Wavelength

Matter Waves: de Broglie Wavelength question from MHT CET 2024 (3 May, Shift 1)

Q59MHT CET 2024 · 3 MAY · SHIFT 1Medium

Matter Waves: de Broglie Wavelength

The ratio of the wavelength of a photon of energy ' $E$ ' to that of the electron of same energy is ( $m =$ mass of an electron, $c =$ speed of light, $h =$ Planck's constant)

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Answer: (d)

$\lambda_{ph} = \dfrac{hc}{E}$ , $\lambda_e = \dfrac{h}{\sqrt{2mE}}$ .
$\dfrac{\lambda_{ph}}{\lambda_e} = \dfrac{c\sqrt{2mE}}{E} = c\sqrt{\dfrac{2m}{E}}$
So the answer is (d).

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