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MHT CET 2025 (19 Apr, Shift 1) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from MHT CET 2025 (19 Apr, Shift 1)

Q10MHT CET 2025 · 19 APR · SHIFT 1Easy

Hydrogen Spectrum & Spectral Series

The ratio of the wavelength of the last line of Paschen series to that of Balmer series is

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Answer: (a)

  1. Last line = series limit: λ=n12R\lambda = \frac{n_1^2}{R}.
  2. Paschen: 9R\frac{9}{R}; Balmer: 4R\frac{4}{R}.
  3. Ratio =94= \frac{9}{4}.
  4. So the answer is (a) 94\frac{9}{4}.
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