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MHT CET 2026 (18 Apr, Shift 1) · Heat Conduction

Heat Conduction question from MHT CET 2026 (18 Apr, Shift 1)

Q3MHT CET 2026 · 18 APR · SHIFT 1Easy

Heat Conduction

The ratio of thermal conductivity of two rods of different materials is 4:34 : 3. The two rods have same area of cross-section and same thermal resistance. The lengths of rods are in the ratio

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Answer: (b)

  1. Thermal resistance R=LKAR = \frac{L}{KA}; same RR and AA gives L∝KL \propto K.
  2. L1L2=K1K2=43\frac{L_1}{L_2} = \frac{K_1}{K_2} = \frac{4}{3}
  3. So the answer is (b) 4:34:3.
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