Physics Circle home Student Login

Home›Chapters›Atomic Structure PYQs›Hydrogen Spectrum & Spectral Series›Question 37

JEE Main 2023 (8 Apr, Shift 2) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from JEE Main 2023 (8 Apr, Shift 2)

Q37JEE Main 2023 · 8 APR · SHIFT 2Medium

Hydrogen Spectrum & Spectral Series

The ratio of wavelength of spectral lines Hα\text{H}_\alpha and Hβ\text{H}_\beta in the Balmer series is x20\frac{x}{20}. The value of xx is _________.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 27

  1. HαH_\alpha (3→23 \to 2): 1λα=5R36\frac{1}{\lambda_\alpha} = \frac{5R}{36}; HβH_\beta (4→24 \to 2): 1λβ=3R16\frac{1}{\lambda_\beta} = \frac{3R}{16}
  2. λαλβ=3/165/36=10880=2720\frac{\lambda_\alpha}{\lambda_\beta} = \frac{3/16}{5/36} = \frac{108}{80} = \frac{27}{20}
  3. Answer: x=27x = 27
Report a mistake

More questions on Hydrogen Spectrum & Spectral Series