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JEE Main 2016 (9 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2016 (9 Apr, Shift 1)

Q222JEE Main 2016 · 9 APR · SHIFT 1Easy

Thermodynamic Processes

The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is:

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Answer: (d)

Isobaric: $W = nR\Delta T$ , $Q = nC_p\Delta T$ .
Monoatomic: $C_p = \frac{5}{2}R$ .
$\frac{W}{Q} = \frac{R}{\frac{5}{2}R} = \frac{2}{5}$
So the answer is (d) $\frac{2}{5}$ .

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