The reading of pressure metre attached with a closed pipe is 4.5 × 10⁴ N/m². On opening the valve, water starts flowing and the reading of pressure metre falls to 2.0 × 10⁴ N/m². The velocity of water is found to be √(V) m/s. The value of V is _________. Numerical answer type. Work it out, then open the answer.

Answer: 50. Fall in static pressure becomes kinetic energy: Δ P = 1/2ρ v² 4.5×10⁴ - 2.0×10⁴ = 1/2(1000)v² ⇒ v² = 50 So V = 50.

The reading of pressure metre attached with a closed pipe is 4.5 ×… | JEE Main 2024 (27 Jan, Shift 2)

Q13JEE Main 2024 · 27 JAN · SHIFT 2Medium

Velocity of Efflux (Torricelli)

The reading of pressure metre attached with a closed pipe is $4.5 \times 10^{4}\text{ N/m}^2$ . On opening the valve, water starts flowing and the reading of pressure metre falls to $2.0 \times 10^{4}\text{ N/m}^2$ . The velocity of water is found to be $\sqrt{V}\text{ m/s}$ . The value of $V$ is _________.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 50

Fall in static pressure becomes kinetic energy: $\Delta P = \frac{1}{2}\rho v^2$
$4.5\times10^{4} - 2.0\times10^{4} = \frac{1}{2}(1000)v^2 \Rightarrow v^2 = 50$
So $V = 50$ .

Report a mistake

Velocity of Efflux (Torricelli) question from JEE Main 2024 (27 Jan, Shift 2)

More questions on Velocity of Efflux (Torricelli)