Physics Circle home Student Login

Home›Chapters›Ray Optics PYQs›Prism, Dispersion & Scattering›Question 80

NEET 2015 (AIPMT, Cancelled Paper) · Prism, Dispersion & Scattering

Prism, Dispersion & Scattering question from NEET 2015 (AIPMT, Cancelled Paper)

Q80NEET 2015 · AIPMT · CANCELLED PAPERMedium

Prism, Dispersion & Scattering

The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A/2). The angle of minimum deviation is

Show answer and solution

Answer: (d)

  1. μ=sin⁡A+δm2sin⁡A2=cot⁡A2⇒sin⁡A+δm2=cos⁡A2\mu = \dfrac{\sin\frac{A+\delta_m}{2}}{\sin\frac{A}{2}} = \cot\frac{A}{2} \Rightarrow \sin\frac{A+\delta_m}{2} = \cos\frac{A}{2}
  2. A+δm2=90∘−A2\frac{A+\delta_m}{2} = 90^\circ - \frac{A}{2}
  3. δm=180∘−2A\delta_m = 180^\circ - 2A
  4. So the answer is (d).
Report a mistake

More questions on Prism, Dispersion & Scattering