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MHT CET 2025 (23 Apr, Shift 2) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2025 (23 Apr, Shift 2)

Q23MHT CET 2025 · 23 APR · SHIFT 2Medium

Current Loop as a Magnetic Dipole

The relation between magnetic moment (M)(M) of a current carrying circular coil and length (L) of the wire used is

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Answer: (c)

  1. Single-turn circle: 2πr=L⇒r=L2π2\pi r = L \Rightarrow r = \frac{L}{2\pi}.
  2. M=Iπr2=IL24πM = I\pi r^2 = \frac{IL^2}{4\pi}
  3. So the answer is (c) M∝L2M \propto L^2.
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