Physics Circle home Student Login

Home›Chapters›Moving Charges and Magnetism PYQs›Current Loop as a Magnetic Dipole›Question 13

MHT CET 2026 (20 May, Shift 1) · Current Loop as a Magnetic Dipole

Current Loop as a Magnetic Dipole question from MHT CET 2026 (20 May, Shift 1)

Q13MHT CET 2026 · 20 MAY · SHIFT 1Medium

Current Loop as a Magnetic Dipole

The relation between magnetic moment (M) of revolving electron of charge (e) and mass (m) having principle quantum number (n) is (h = Planck's constant)

Show answer and solution

Answer: (a)

  1. For an orbiting electron M=e2mLM = \frac{e}{2m}L.
  2. Bohr's rule: L=nh2πL = \frac{nh}{2\pi}.
  3. M=e2m⋅nh2π=neh4πmM = \frac{e}{2m}\cdot\frac{nh}{2\pi} = \frac{neh}{4\pi m}
  4. So the answer is (a) Mn=eh4πm\frac{M}{n} = \frac{eh}{4\pi m}.
Report a mistake

More questions on Current Loop as a Magnetic Dipole