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JEE Main 2005 (AIEEE) · Velocity, Acceleration & Variable Motion

Velocity, Acceleration & Variable Motion question from JEE Main 2005 (AIEEE)

Q45JEE Main 2005 · AIEEEMedium

Velocity, Acceleration & Variable Motion

The relation between time t and distance x is t = ax2 + bx where a and b are constants. The acceleration is

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Answer: (d)

  1. dtdx=2ax+b=1v\dfrac{dt}{dx} = 2ax + b = \dfrac{1}{v}
  2. Differentiate w.r.t. tt: 2av=−1v2dvdt2av = -\dfrac{1}{v^2}\dfrac{dv}{dt}
  3. acc=dvdt=−2av3a_{cc} = \dfrac{dv}{dt} = -2av^3
  4. So the answer is (d).
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