The relationship between the magnetic susceptibility ( χ) and magnetic permeability ( μ) of a material is ( μ₀ and μr is the permeability of free space and relative permeability respectively) (a) χ = (μ)/(μ₀) - 1 (b) χ = (μr)/(μ₀) + 1 (c) χ = μr + 1 (d) χ = 1 - (μ)/(μ₀)

Answer: (a). μr = 1 + χ and μr = μ/μ₀. χ = μr - 1 = (μ)/(μ₀) - 1 So the answer is (a).

The relationship between the magnetic susceptibility ( χ) and… | MHT CET 2026 (15 May, Shift 2)

Q5MHT CET 2026 · 15 MAY · SHIFT 2Easy

Magnetisation: B, H, M, χ & μ

The relationship between the magnetic susceptibility ( $\chi$ ) and magnetic permeability ( $\mu$ ) of a material is ( $\mu_0$ and $\mu_r$ is the permeability of free space and relative permeability respectively)

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Answer: (a)

$\mu_r = 1 + \chi$ and $\mu_r = \mu/\mu_0$ .
$\chi = \mu_r - 1 = \dfrac{\mu}{\mu_0} - 1$
So the answer is (a).

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Magnetisation: B, H, M, χ & μ question from MHT CET 2026 (15 May, Shift 2)

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