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JEE Main 2025 (2 Apr, Shift 1) · Magnetisation: B, H, M, χ & μ

Magnetisation: B, H, M, χ & μ question from JEE Main 2025 (2 Apr, Shift 1)

Q16JEE Main 2025 · 2 APR · SHIFT 1Easy

Magnetisation: B, H, M, χ & μ

The relationship between the magnetic susceptibility (χ)(\chi) and the magnetic permeability (μ)(\mu) is given by:

( μ0\mu_0 is the permeability of free space and μr\mu_r is relative permeability)

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Answer: (a)

  1. μr=μ/μ0=1+χ\mu_r = \mu/\mu_0 = 1 + \chi.
  2. χ=μμ0−1\chi = \dfrac{\mu}{\mu_0} - 1
  3. So the answer is (a).
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