Physics Circle home Student Login

Home›Chapters›Current Electricity PYQs›Ohm's Law, Resistivity & Temperature›Question 32

JEE Main 2021 (27 Jul, Shift 2) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2021 (27 Jul, Shift 2)

Q32JEE Main 2021 · 27 JUL · SHIFT 2Easy

Ohm's Law, Resistivity & Temperature

The resistance of a conductor at 15∘^\circC is 16Ω\Omega and at 100∘^\circ C is 20Ω\Omega. What will be the temperature coefficient of resistance of the conductor?

Show answer and solution

Answer: (c)

  1. Use Rt=R0(1+αt)R_t = R_0(1 + \alpha t): 2016=1+100α1+15α\dfrac{20}{16} = \dfrac{1 + 100\alpha}{1 + 15\alpha}
  2. 20+300α=16+1600α⇒1300α=420 + 300\alpha = 16 + 1600\alpha \Rightarrow 1300\alpha = 4
  3. α≈0.003 ∘C−1\alpha \approx 0.003\ ^\circ\text{C}^{-1}
  4. So the answer is (c) 0.003 ∘C−10.003\ ^\circ\text{C}^{-1}.
Report a mistake

More questions on Ohm's Law, Resistivity & Temperature