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JEE Main 2019 (9 Apr, Shift 2) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2019 (9 Apr, Shift 2)

Q152JEE Main 2019 · 9 APR · SHIFT 2Easy

Kirchhoff's Laws & Measuring Instruments

The resistance of a galvanometer is 50 ohm and the maximum current which can be passed through it is 0.002 A. What resistance must be connected to it in order to convert it into an ammeter of range 0 – 0.5 A?

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Answer: (b)

A shunt is needed: $S = \frac{I_g G}{I - I_g}$ .
$S = \frac{0.002 \times 50}{0.5 - 0.002} = \frac{0.1}{0.498} \approx 0.2\text{ ohm}$
So the answer is (b) 0.2 ohm.

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