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JEE Main 2004 (AIEEE) · Combination of Resistors

Combination of Resistors question from JEE Main 2004 (AIEEE)

Q76JEE Main 2004 · AIEEEMedium

Combination of Resistors

The resistance of the series combination of two resistances is S.S. When they are joined in parallel the total resistance is P.P. If S=nPS = nP then the minimum possible value of nn is

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Answer: (c)

  1. S=R1+R2S = R_1 + R_2, P=R1R2R1+R2P = \dfrac{R_1 R_2}{R_1 + R_2}, so n=SP=(R1+R2)2R1R2n = \dfrac{S}{P} = \dfrac{(R_1 + R_2)^2}{R_1 R_2}.
  2. By AM–GM, (R1+R2)2≥4R1R2(R_1 + R_2)^2 \ge 4R_1R_2, so n≥4n \ge 4 (equality when R1=R2R_1 = R_2).
  3. So the answer is (c) 4.
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