The resistance R = V/I where V = (200 ± 5) V and I = (20 ± 0.2) A, the percentage error in the measurement of R is: (a) 5.5% (b) 3% (c) 7% (d) 3.5%

Answer: (d). (Δ R)/(R) = (Δ V)/(V) + (Δ I)/(I) = 5/200 + 0.2/20 = 2.5% + 1% = 3.5% So the answer is (d) 3.5%.

The resistance R = V/I where V = (200 ± 5) V and I = (20 ± 0.2) A… | JEE Main 2024 (29 Jan, Shift 1)

Q61JEE Main 2024 · 29 JAN · SHIFT 1Easy

Errors in Measurement

The resistance $R = \frac{V}{I}$ where $V = (200 \pm 5)\text{ V}$ and $I = (20 \pm 0.2)\text{ A}$ , the percentage error in the measurement of $R$ is:

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Answer: (d)

$\frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}$
$= \frac{5}{200} + \frac{0.2}{20} = 2.5\% + 1\% = 3.5\%$
So the answer is (d) 3.5%.

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