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JEE Main 2021 (16 Mar, Shift 1) · Errors in Measurement

Errors in Measurement question from JEE Main 2021 (16 Mar, Shift 1)

Q82JEE Main 2021 · 16 MAR · SHIFT 1Medium

Errors in Measurement

The resistance R = VI\frac{V}{I}, where V = (50 ±\pm 2)V and I = (20 ±\pm 0.2)A. The percentage error in R is 'x'%. The value of 'x' to the nearest integer is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. R=VI⇒ΔRR=ΔVV+ΔIIR = \frac{V}{I} \Rightarrow \frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I}
  2. =250+0.220=4%+1%=5%= \frac{2}{50} + \frac{0.2}{20} = 4\% + 1\% = 5\%
  3. Answer: x=5x = 5.
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