The resistances of the platinum wire of a platinum resistance thermometer at the ice point and steam point are 8 Ω and 10 Ω respectively. After inserting in a hot bath of temperature 400, the resistance of platinum wire is: (a) 10 Ω (b) 16 Ω (c) 8 Ω (d) 2 Ω

Answer: (b). t/100=Rt-R₀R₁₀₀-R₀ (400)/(100)=(R-8)/(10-8)⇒ R-8=8 R=16 Ω So the answer is (b) 16 Ω.

The resistances of the platinum wire of a platinum resistance… | JEE Main 2024 (4 Apr, Shift 1)

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Thermometry & Thermal Expansion

The resistances of the platinum wire of a platinum resistance thermometer at the ice point and steam point are $8\ \Omega$ and $10\ \Omega$ respectively. After inserting in a hot bath of temperature $400^\circ\text{C}$ , the resistance of platinum wire is:

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Answer: (b)

$\frac{t}{100}=\frac{R_t-R_0}{R_{100}-R_0}$
$\frac{400}{100}=\frac{R-8}{10-8}\Rightarrow R-8=8$
$R=16\ \Omega$
So the answer is (b) 16 $\Omega$ .

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