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MHT CET 2026 (17 Apr, Shift 1) · Series LCR Circuit

Series LCR Circuit question from MHT CET 2026 (17 Apr, Shift 1)

Q11MHT CET 2026 · 17 APR · SHIFT 1Medium

Series LCR Circuit

The resistor 'RR' inductance 'LL' and capacitance 'CC' are connected in series with an a.c. source. When 'L' is removed from the circuit, the phase difference between voltage and current in the circuit is π3\frac{\pi}{3}. If instead, C is removed from the circuit, the phase difference is again π3\frac{\pi}{3}. The power factor of the circuit is

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Answer: (d)

  1. L removed: XC=Rtan⁡π3=3RX_C = R\tan\dfrac{\pi}{3} = \sqrt{3}R.
  2. C removed: XL=Rtan⁡π3=3RX_L = R\tan\dfrac{\pi}{3} = \sqrt{3}R.
  3. XL=XC⇒X_L = X_C \Rightarrow resonance, Z=RZ = R.
  4. Power factor =RZ=1= \dfrac{R}{Z} = 1. So the answer is (d) 11.
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