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MHT CET 2020 (16 Oct, Shift 2) · Addition & Subtraction of Vectors

Addition & Subtraction of Vectors question from MHT CET 2020 (16 Oct, Shift 2)

Q25MHT CET 2020 · 16 OCT · SHIFT 2Medium

Addition & Subtraction of Vectors

The resultant of two vector A\mathbf{A} and B\mathbf{B} is C\mathbf{C}. If the magnitude of B\mathbf{B} is doubled, the new resultant vector becomes perpendicular to A. Then, the magnitude of C\mathbf{C} is

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Answer: (b)

  1. (A⃗+2B⃗)⋅A⃗=0⇒A2+2ABcos⁡θ=0(\vec{A} + 2\vec{B}) \cdot \vec{A} = 0 \Rightarrow A^2 + 2AB\cos\theta = 0
  2. C2=A2+B2+2ABcos⁡θ=B2⇒C=BC^2 = A^2 + B^2 + 2AB\cos\theta = B^2 \Rightarrow C = B
  3. So the answer is (b) B.
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