The resultant R of P and Q is perpendicular to P. Also |P| = |R|. The angle between P and Q is ( tan 45° = 1) (a) π/4 (b) 3π/4 (c) 5π/4 (d) 7π/4

Answer: (b). PRQ135° Take P = Pi. R ⊥ P and |R| = P, so R = Pj. Q = R - P = -Pi + Pj Q points at 135° to +x, i.e. to P. So the answer is (b) 3π/4.

The resultant R of P and Q is perpendicular to P. Also |P| = |R|. The… | MHT CET 2026 (14 May, Shift 2)

Q4MHT CET 2026 · 14 MAY · SHIFT 2Medium

Addition & Subtraction of Vectors

The resultant $\vec{R}$ of $\vec{P}$ and $\vec{Q}$ is perpendicular to $\vec{P}$ . Also $|\vec{P}| = |\vec{R}|$ . The angle between $\vec{P}$ and $\vec{Q}$ is ( $\tan 45^\circ = 1$ )

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Answer: (b)

Take $\vec{P} = P\hat{i}$ . $\vec{R} \perp \vec{P}$ and $|\vec{R}| = P$ , so $\vec{R} = P\hat{j}$ .
$\vec{Q} = \vec{R} - \vec{P} = -P\hat{i} + P\hat{j}$
$\vec{Q}$ points at $135^\circ$ to $+x$ , i.e. to $\vec{P}$ .
So the answer is (b) $\frac{3\pi}{4}$ .

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Addition & Subtraction of Vectors question from MHT CET 2026 (14 May, Shift 2)

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