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MHT CET 2026 (20 Apr, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2026 (20 Apr, Shift 1)

Q8MHT CET 2026 · 20 APR · SHIFT 1Easy

Self-Inductance & Energy

The self inductance of an air-core inductor (solenoid) is $0.03$ mH. By introducing an iron core into inductor the self-inductance increases to $30$ mH. The relative permeability of the core used is

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Answer: (d)

With a core, $L = \mu_r L_0$ .
$\mu_r = \dfrac{L}{L_0} = \dfrac{30}{0.03} = 1000$
So the answer is (d) $10^{3}$ .

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