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MHT CET 2023 (14 May, Shift 2) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2023 (14 May, Shift 2)

Q55MHT CET 2023 · 14 MAY · SHIFT 2Easy

Self-Inductance & Energy

The self induction (L) produced by solenoid of length ' $l$ ' having ' $N$ ' number of turns and cross sectional area ' $A$ ' is given by the formula ( $\phi =$ magnetic flux, $\mu_0 =$ permeability of vacuum)

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Answer: (c)

Field inside: $B = \dfrac{\mu_0 N I}{l}$ ; total flux linkage $N\phi = N\,BA = \dfrac{\mu_0 N^2 A I}{l}$ .
$L = \dfrac{N\phi}{I} = \dfrac{\mu_0 N^2 A}{l}$
So the answer is (c) $L = \dfrac{\mu_0 N^2 A}{l}$ .

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