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MHT CET 2021 (23 Sep, Shift 1) · Hydrogen Spectrum & Spectral Series

Hydrogen Spectrum & Spectral Series question from MHT CET 2021 (23 Sep, Shift 1)

Q42MHT CET 2021 · 23 SEP · SHIFT 1Medium

Hydrogen Spectrum & Spectral Series

The shortest wavelength for Lyman series is 912 A˚\text{Å}. The longest wavelength in Paschen series is

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Answer: (c)

  1. Lyman shortest: λ=1R=912 A˚\lambda = \frac{1}{R} = 912\ \text{Å}
  2. Paschen longest (4→34 \to 3): 1λ=R(19−116)=7R144\frac{1}{\lambda} = R\left(\frac{1}{9}-\frac{1}{16}\right) = \frac{7R}{144}
  3. λ=1447×912≈18760 A˚\lambda = \frac{144}{7}\times 912 \approx 18760\ \text{Å}
  4. So the answer is (c) 18760 Å.
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