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JEE Main 2022 (27 Jun, Shift 2) · Units & Dimensions

Units & Dimensions question from JEE Main 2022 (27 Jun, Shift 2)

Q45JEE Main 2022 · 27 JUN · SHIFT 2Easy

Units & Dimensions

The SI unit of a physical quantity is pascal-second. The dimensional formula of this quantity will be:

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Answer: (a)

  1. Pascal is pressure: [ML−1T−2][\mathrm{ML^{-1}T^{-2}}].
  2. Pa s →[ML−1T−2][T]=[ML−1T−1]\to [\mathrm{ML^{-1}T^{-2}}][\mathrm{T}] = [\mathrm{ML^{-1}T^{-1}}] (this is viscosity).
  3. So the answer is (a) [ML−1T−1][\mathrm{ML^{-1}T^{-1}}].
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