The side of a copper cube is 1 m at 0. What will be the change in its volume, when it is heated to 100? [α copper = 18 × 10⁻⁶/] (a) 45 × 10⁻⁴ m³ (b) 54 × 10⁻⁴ m³ (c) 34 × 10⁻⁴ m³ (d) 64 × 10⁻⁴ m³

Answer: (b). Δ V = V(3α)Δ T with V = 1 m³. Δ V = 1 × 3 × 18×10⁻⁶ × 100 = 5.4×10⁻³ m³ So the answer is (b) 54×10⁻⁴ m³.

The side of a copper cube is 1 m at 0. What will be the change in its… | MHT CET 2023 (9 May, Shift 2)

Q38MHT CET 2023 · 9 MAY · SHIFT 2Medium

Thermometry & Thermal Expansion

The side of a copper cube is $1\text{ m}$ at $0^\circ\text{C}$ . What will be the change in its volume, when it is heated to $100^\circ\text{C}$ ? $[\alpha$ copper $= 18 \times 10^{-6}/^\circ\text{C}]$

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Answer: (b)

$\Delta V = V(3\alpha)\Delta T$ with $V = 1\text{ m}^3$ .
$\Delta V = 1 \times 3 \times 18\times10^{-6} \times 100 = 5.4\times10^{-3}\text{ m}^3$
So the answer is (b) $54\times10^{-4}\text{ m}^3$ .

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Thermometry & Thermal Expansion question from MHT CET 2023 (9 May, Shift 2)

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