The sliding contact C is at one fourth of the length of the… | NEET 2022 (Phase 2)

Q108NEET 2022 · PHASE 2Medium

Kirchhoff's Laws & Measuring Instruments

The sliding contact C is at one fourth of the length of the potentiometer wire (AB) from A as shown in the circuit diagram. If the resistance of the wire AB is R0, then the potential drop (V) across the resistor R is

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Answer: (b)

AC has $\frac{R_0}{4}$ and is in parallel with $R$ ; CB has $\frac{3R_0}{4}$ in series.
$R_{AC} \parallel R = \frac{(R_0/4)R}{R_0/4 + R} = \frac{R_0 R}{R_0 + 4R}$
Voltage divider: $V = V_0 \frac{\frac{R_0R}{R_0+4R}}{\frac{R_0R}{R_0+4R} + \frac{3R_0}{4}} = \frac{4V_0R}{4R + 3(R_0 + 4R)}$
$V = \frac{4V_0R}{3R_0 + 16R}$
So the answer is (b).

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