The specific heat of argon at constant pressure and constant volume are Cp and Cv respectively. It's density ' ρ ' at N.T.P. will be [P and T are pressure and temperature respectively at N.T.P.] (a) (P)/(T(Cp - Cv)) (b) (PT)/((Cp - Cv)) (c) (T(Cp - Cv))/(P) (d) ((Cp - Cv))/(PT)

Answer: (a). Ideal gas: ρ = PM/RT. Specific heats per unit mass: Cp - Cv = R/M ⇒ M/R = (1)/(Cp - Cv) ρ = (P)/(T(Cp - Cv)) So the answer is (a).

The specific heat of argon at constant pressure and constant volume… | MHT CET 2024 (3 May, Shift 2)

Q21MHT CET 2024 · 3 MAY · SHIFT 2Difficult

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

The specific heat of argon at constant pressure and constant volume are $C_p$ and $C_v$ respectively. It's density ' $\rho$ ' at N.T.P. will be $[P$ and T are pressure and temperature respectively at N.T.P.]

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Answer: (a)

Ideal gas: $\rho = \dfrac{PM}{RT}$ .
Specific heats per unit mass: $C_p - C_v = \dfrac{R}{M} \Rightarrow \dfrac{M}{R} = \dfrac{1}{C_p - C_v}$
$\rho = \dfrac{P}{T(C_p - C_v)}$
So the answer is (a).

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from MHT CET 2024 (3 May, Shift 2)

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