Physics Circle home Student Login

Home›Chapters›Thermodynamics PYQs›Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation›Question 51

JEE Main 2019 (9 Apr, Shift 2) · Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from JEE Main 2019 (9 Apr, Shift 2)

Q51JEE Main 2019 · 9 APR · SHIFT 2Medium

Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

The specific heats, CP and CV of a gas of diatomic molecules, A, are given (in units of J mol–1 K–1) by 29 and 22, respectively. Another gas of diatomic molecules, B, has the corresponding values 30 and 21. If they are treated as ideal gases, then :-

Show answer and solution

Answer: (b)

  1. Rigid diatomic: CV=52R≈20.8C_V = \dfrac{5}{2}R \approx 20.8 J/mol K; a vibrational mode raises it towards 72R≈29\dfrac{7}{2}R \approx 29.
  2. Gas A: CV=22>20.8C_V = 22 > 20.8, so extra energy goes into vibration: A has a vibrational mode.
  3. Gas B: CV=21≈52RC_V = 21 \approx \dfrac{5}{2}R, so B is rigid.
  4. So the answer is (b) A has a vibrational mode but B has none.
Report a mistake

More questions on Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation