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JEE Main 2020 (4 Sep, Shift 2) · Graphs of Motion

Graphs of Motion question from JEE Main 2020 (4 Sep, Shift 2)

Q27JEE Main 2020 · 4 SEP · SHIFT 2Easy

Graphs of Motion

The speed versus time graph for a particle is shown in the figure. The distance travelled (in m) by the particle during the time interval t = 0 to t = 5 s will be________.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 20

  1. Distance = area under the speed-time graph.
  2. The line passes through the origin and reaches 8 m/s8\text{ m/s} at t=5 st = 5\text{ s}.
  3. Area =12×5×8=20= \frac{1}{2}\times 5\times 8 = 20
  4. Distance =20 m= 20\text{ m}
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