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MHT CET 2024 (15 May, Shift 2) · Photoelectric Experiment: Intensity, Stopping Potential & Graphs

Photoelectric Experiment: Intensity, Stopping Potential & Graphs question from MHT CET 2024 (15 May, Shift 2)

Q30MHT CET 2024 · 15 MAY · SHIFT 2Easy

Photoelectric Experiment: Intensity, Stopping Potential & Graphs

The stopping potential as a function of frequency of incident radiation is plotted for two different photoelectric surfaces A and B. The graph shows that the work function of A is

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Answer: (b)

$V_0 = \dfrac{h}{e}(\nu - \nu_0)$ ; each line meets the $\nu$ axis at its threshold frequency $\nu_0$ .
From the graph, $\nu_{0A} < \nu_{0B}$ .
$\phi = h\nu_0$ , so $\phi_A < \phi_B$ .
So the answer is (b) smaller than that of B.

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