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MHT CET 2024 (2 May, Shift 2) · Photoelectric Effect: Einstein's Equation

Photoelectric Effect: Einstein's Equation question from MHT CET 2024 (2 May, Shift 2)

Q52MHT CET 2024 · 2 MAY · SHIFT 2Easy

Photoelectric Effect: Einstein's Equation

The stopping potential for a photelectric emission process is 10 V. The maximum kinetic energy of the electrons ejected in the process is [Charge on electron e=1.6×10−19 Ce = 1.6 \times 10^{-19}\text{ C} ]

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Answer: (c)

  1. Kmax=eV0K_{max} = eV_0
  2. Kmax=1.6×10−19×10=1.6×10−18 JK_{max} = 1.6 \times 10^{-19} \times 10 = 1.6 \times 10^{-18}\text{ J}
  3. So the answer is (c) 1.6×10−18 J1.6 \times 10^{-18}\text{ J}.
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