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MHT CET 2024 (2 May, Shift 2) · Vertical Circle: Speed & Tension

Vertical Circle: Speed & Tension question from MHT CET 2024 (2 May, Shift 2)

Q11MHT CET 2024 · 2 MAY · SHIFT 2Medium

Vertical Circle: Speed & Tension

The string of pendulum of length ' $L$ ' is displaced through $90^\circ$ from the vertical and released. Then the maximum strength of the string in order to withstand the tension, as the pendulum passes through the mean position is ( $m =$ mass of pendulum, $g =$ acceleration due to gravity)

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Answer: (b)

From $90^\circ$ : $v^2 = 2gL$ at the mean position
$T = mg + \frac{mv^2}{L} = mg + 2mg = 3mg$
So the answer is (b) 3 mg.

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