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MHT CET 2024 (4 May, Shift 1) · Velocity of Efflux (Torricelli)

Velocity of Efflux (Torricelli) question from MHT CET 2024 (4 May, Shift 1)

Q11MHT CET 2024 · 4 MAY · SHIFT 1Medium

Velocity of Efflux (Torricelli)

The surface of water in a water tank of cross section area 750 cm2750\text{ cm}^2 on the top of a house is ' hh ' m\text{m} above the tap level. The speed of water coming out through the tap of cross section area 500 mm2500\text{ mm}^2 is 30 cm/s30\text{ cm/s}. At that instant dhdt\frac{dh}{dt} is x×10−3 m/sx \times 10^{-3}\text{ m/s}. The value of ' xx ' will be

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Answer: (a)

  1. Continuity: A∣dhdt∣=avA\left|\frac{dh}{dt}\right| = a v
  2. ∣dhdt∣=(500×10−6)(0.30)750×10−4=2×10−3 m/s\left|\frac{dh}{dt}\right| = \frac{(500\times10^{-6})(0.30)}{750\times10^{-4}} = 2\times10^{-3}\text{ m/s}
  3. So the answer is (a) x=2x = 2.
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