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MHT CET 2026 (13 Apr, Shift 2) · Velocity of Efflux (Torricelli)

Velocity of Efflux (Torricelli) question from MHT CET 2026 (13 Apr, Shift 2)

Q2MHT CET 2026 · 13 APR · SHIFT 2Medium

Velocity of Efflux (Torricelli)

The surface of water in a water tank of cross-section area 750750 cm2^{2} on the top of a house is hh m above the tap level. The speed of water coming out through the tap of cross-section area 500500 mm2^{2} is 3030 cm/s. At that instant, dh/dtdh/dt is y×10−3y \times 10^{-3} m/s. The value of yy will be

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Answer: (a)

  1. Continuity: A∣dhdt∣=avA\left|\frac{dh}{dt}\right| = a v
  2. ∣dhdt∣=(500×10−6)(0.30)750×10−4=1.5×10−40.075=2×10−3 m/s\left|\frac{dh}{dt}\right| = \frac{(500\times10^{-6})(0.30)}{750\times10^{-4}} = \frac{1.5\times10^{-4}}{0.075} = 2\times10^{-3}\text{ m/s}
  3. So the answer is (a) y=2y = 2.
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