The temperature difference between two sides of an iron plate, 1.8 cm thick is 9. Heat is transmitted through the plate 10 kcal/s m² at steady state. The thermal conductivity of iron is (a) 0.02 (kcal)/(m s) (b) 0.04 (kcal)/(m s) (c) 0.05 (kcal)/(m s) (d) 0.004 (kcal)/(m s)

Answer: (a). Heat flux H/A = (KΔ T)/(d) ⇒ K = ((H/A) d)/(Δ T) K = (10 × 0.018)/(9) = 0.02 kcal m⁻¹s⁻¹ ⁻¹ So the answer is (a).

The temperature difference between two sides of an iron plate, 1.8 cm… | MHT CET 2021 (24 Sep, Shift 1)

Q32MHT CET 2021 · 24 SEP · SHIFT 1Easy

Heat Conduction

The temperature difference between two sides of an iron plate, $1.8\text{ cm}$ thick is $9^\circ\text{C}$ . Heat is transmitted through the plate $10\text{ kcal/s m}^2$ at steady state. The thermal conductivity of iron is

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Answer: (a)

Heat flux $\frac{H}{A} = \frac{K\Delta T}{d} \Rightarrow K = \frac{(H/A)\,d}{\Delta T}$
$K = \frac{10 \times 0.018}{9} = 0.02\ \text{kcal m}^{-1}\text{s}^{-1}\,{}^\circ\text{C}^{-1}$
So the answer is (a).

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Heat Conduction question from MHT CET 2021 (24 Sep, Shift 1)

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