The temperature difference bewtween two sides of metal plate, 3 cm thick is 15. Heat is transmitted through plate at the rate of 900 kcal per minute per m² at steady state. The thermal conductivity of metal is (a) 1.8 × 10⁻² (kcal)/(m s) (b) 4.5 × 10⁻² (kcal)/(m s) (c) 3 × 10⁻² (kcal)/(m s) (d) 6 × 10⁻² (kcal)/(m s)

Answer: (c). Heat flux = 900/60 = 15 kcal s⁻¹m⁻² K = ((H/A) d)/(Δ T) = (15 × 0.03)/(15) K = 3 × 10⁻² kcal m⁻¹s⁻¹ ⁻¹, so the answer is (c).

The temperature difference bewtween two sides of metal plate, 3 cm… | MHT CET 2021 (21 Sep, Shift 1)

Q36MHT CET 2021 · 21 SEP · SHIFT 1Medium

Heat Conduction

The temperature difference bewtween two sides of metal plate, $3\text{ cm}$ thick is $15^\circ\text{C}$ . Heat is transmitted through plate at the rate of $900\text{ kcal}$ per minute per $\text{m}^2$ at steady state. The thermal conductivity of metal is

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Answer: (c)

Heat flux $= \frac{900}{60} = 15\ \text{kcal s}^{-1}\text{m}^{-2}$
$K = \frac{(H/A)\,d}{\Delta T} = \frac{15 \times 0.03}{15}$
$K = 3 \times 10^{-2}\ \text{kcal m}^{-1}\text{s}^{-1}\,{}^\circ\text{C}^{-1}$ , so the answer is (c).

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Heat Conduction question from MHT CET 2021 (21 Sep, Shift 1)

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